Cannot print uint128_t values

Library Questions
1

Hi, just a quick issue (I would have opened it on GitHub, but apparently only contributors can)."
Trying to print a uint128_t value causes the following compilation error:

error: use of overloaded operator '<<' is ambiguous (with operand types 'ostream' (aka 'basic_ostream<char>') and 'uint128_t' (aka 'unsigned __int128'))
   32 |     std::cout << x;

I guess the definition for << is missing, or something like that. The bug is easily replicable, simply write

uint128_t x = 10;
std::cout << x;
2

uint128_t/__uint128_t is not a standard C++ type, it’s a compiler extension. that’s why std::cout does not natively support it.
you can print it with a custom function similar to this:

std::string to_string_uint128(__uint128_t v) {
    if (v == 0)
        return "0";

    std::string s;
    while (v > 0) {
        s.push_back((v % 10) + 48);
        v /= 10;
    }

    std::reverse(s.begin(), s.end());
    return s;
}
3

thank you very much:) i was able to print it eventually, just created this to report the problem